Java Listenin Elemanlarını Sıralamak
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 32 | import java.util.Arrays; import java.util.Collections; import java.util.List; /** * * @author ugur */ public class SortListExample { public static void main(String args[]) { Integer[] intArray = new Integer[] {1,4,2,10,9,8,20,15,3,3,4}; List<Integer> list = Arrays.asList(intArray); Collections.sort(list); for(Integer i : list) { System.out.print(i + " "); } System.out.println(" "); // reverse order Collections.sort(list,Collections.reverseOrder()); for(Integer i : list) { System.out.print(i + " "); } System.out.println(" "); } } |
Output:
run:
1 2 3 3 4 4 8 9 10 15 20
20 15 10 9 8 4 4 3 3 2 1
BUILD SUCCESSFUL (total time: 0 seconds)